0=17x^2+13x-192

Solution for 0=17x^2+13x-192 equation:

0=17x^2+13x-192

We move all terms to the left:

0-(17x^2+13x-192)=0

We add all the numbers together, and all the variables

-(17x^2+13x-192)=0

We get rid of parentheses

-17x^2-13x+192=0

a = -17; b = -13; c = +192;
Δ = b2-4ac
Δ = -132-4·(-17)·192
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13225}=115$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-115}{2*-17}=\frac{-102}{-34}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+115}{2*-17}=\frac{128}{-34}
=-3+13/17
$